What is the smallest value that, when divided by 8, 12, 16, and 20, leaves a remainder of 5?
বিকল্পসমূহ (নিজের উত্তর যাচাই করতে ক্লিক করুন):
সঠিক উত্তর
3 (245)
বিস্তারিত ব্যাখ্যা ও বিশ্লেষণ:
Solution:
We have to find the Least number, therefore we find out the LCM of 8, 12, 16 and 20.
8 = 2 × 2 × 2;
12 = 2 × 2 × 3;
16 = 2 × 2 × 2 × 2;
20 = 2 × 2 × 5;
LCM = 2 × 2 × 2 × 2 × 3 × 5 = 240;
This is the least number which is exactly divisible by 8, 12, 16 and 20
Thus, The required number which leaves the remaining 5 is,
240 + 5 = 245
