Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
বিকল্পসমূহ (নিজের উত্তর যাচাই করতে ক্লিক করুন):
সঠিক উত্তর
ক (2 times)
বিস্তারিত ব্যাখ্যা ও বিশ্লেষণ:
Let Ronit's present age be x years.
Then, father's present age =(x + 3x) years
= 4x years
Now
4x + 8 = (5/2)(x + 8)
8x + 16 = 5x + 40
8x - 5x = 40 - 16
3x = 24
x = 8
Further 8 years will means 16 years from the current age.
After 16 years from present, Ronit's age be (8 + 16) = 24 years
After 16 years from present, father's age be (8 × 4 + 16) = 48 years
After 16 years from present the ratio of their ages will be
His father's age/ Ronit's age = 48/24
His father's age/ Ronit's age =2
His father's age = 2 × Ronit age
