বিসিএস, ব্যাংক, প্রাথমিক শিক্ষক ও সকল সরকারি চাকরির বিগত সালের প্রশ্ন ও অধ্যায়ভিত্তিক নির্ভুল সমাধান
Solution:
Profit for first Tk. 1000 = 1000(5/100)
= Tk. 50
Total sales excess of Tk. 1000 = (12000 - 1000)
= Tk. 11000
∴ Profit for excess of Tk. 1000 = 11000(4/100)
= Tk. 440
∴ Total Profit = (50 + 440) = Tk. 490
Solution:
After 3 days, food having for = (30 - 3) = 27 days
After arriving 300 men, total men = (600 + 300) = 900 men
600 men can eat the food for 27 days
∴ 1 man can eat the food for (27 × 600) days
∴ 900 men can eat the food for (27 × 600)/900 days = 18 days
Solution:
Whole work is done by A in (3 × 4) = 12 days
∴ A's 1 day's work = 1/12 part
Whole work is done by B in (4 × 9) = 36 days
∴ B's 1 day's work = 1/36 part
A's 1 day's work : B's 1 day's work
= A's wages : B's wages
= 1/12 : 1/36
= 3 : 1
∴ A's share = (800 × 3/4) Tk = 600 Tk
Solution:
Here, Days needed = (42 - 9) = 33 days
To complete the work in 42 days, it requires 55 men
To complete the work in 1 days, it requires (55 × 42) men
To complete the work in 33 days, it requires (55× 42)/33 men = 70 men
∴ additional men required = (70 - 55) men = 15 men
Solution:
Here,
B's 1 day's work = 1/20 part
C's 1 day's work = 1/30 part
∴ (B + C)'s 1 day's work = (1/20 + 1/30) part
∴ (B+C)'s 2 day's work = {(1/20 + 1/30) × 2} part = [{(3+2)/60} × 2] part
= (5/60 × 2) part
= 1/6 part
Remaining work = (1 -1/6) part
= 5/6 part
A's one day's work = 1/18 part
∴ The time taken by A alone to complete the remaining work is = (5/6)/(1/18) days = 15 days
